find the point at which the tangent to the curve y=underroot(4x-3) -1 has its slope 2/3.this is the ncert question , after solving this question we get x=3,when we put this value of x in the expression of y we get root(9)-1 . so my doubt is why we do not take +3 and – 3 instead of just +3 as solved in ncert class 12 textbook(applications of derivatives).
find the point at which the tangent to the curve y=underroot(4x-3) -1 has its slope 2/3.
this is the ncert question , after solving this question we get x=3,when we put this value of x in the expression of y we get root(9)-1 . so my doubt is why we do not take +3 and – 3 instead of just +3 as solved in ncert class 12 textbook(applications of derivatives).
shruti , 8 Years ago
Grade 12
