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Find the periodf(x)=[sin3x]+|cos6x|Thanks

vineet nimesh , 10 Years ago
Grade
anser 1 Answers
Jitender Singh

Last Activity: 10 Years ago

Ans:
f(x) = [sin(3x)] + |cos(6x)|
f(x) = f_{1}(x) + f_{2}(x)
f_{1}(x) = [sin(3x)]
= 0, 0\leq x\leq \frac{\pi }{3}
= -1, \frac{\pi }{3}\leq x\leq \frac{2\pi }{3}
Time period of f1(x):
\frac{2\pi }{3} = \frac{4\pi }{6}
f_{2}(x) = |cos(6x)|
Time period of f2(x):
\frac{\pi }{6}
Time period of f(x):
(LCM of time period of f1(x) & f2(x))/(HCFof time period of f1(x) & f2(x))
\frac{4\pi }{6} = \frac{2\pi }{3}
Thanks & Regards
Jitender Singh
IIT Delhi
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