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Grade: 11

                        

Find the max Value of F to move the blocks without slip

7 months ago

Answers : (2)

Manish kumar
25 Points
							
maxium friction force between blocks = 1/2×5×10=25n
maximum accn  5kg block = 25/5= 5m/s2
Fmax= (total mass) ×accnmax = 15×5 =75m/s2
6 months ago
Vikas TU
12281 Points
							
Dear student
Maxium allowable friction force between blocks = 1/2×5×10=25N
Maximum acceleration on   5kg block = maximum allowable frictional force / mass 
= 25/5= 5m/s2
Fmax= (total mass) ×accnmax = 15×5 =75 N 
Good Luck 
6 months ago
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