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Find the max Value of F to move the blocks without slip

```
7 months ago

Manish kumar
25 Points
```							maxium friction force between blocks = 1/2×5×10=25nmaximum accn  5kg block = 25/5= 5m/s2Fmax= (total mass) ×accnmax = 15×5 =75m/s2
```
6 months ago
Vikas TU
12281 Points
```							Dear studentMaxium allowable friction force between blocks = 1/2×5×10=25NMaximum acceleration on   5kg block = maximum allowable frictional force / mass = 25/5= 5m/s2Fmax= (total mass) ×accnmax = 15×5 =75 N Good Luck
```
6 months ago
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### Course Features

• 51 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions