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Find the local maximum of f(x)={ log(x) } / x . I tried but could only find local minima .After first derivate making it equal to 0,i got only one solution i.e., x=e and this solution gave local minima.Please help me in finding local maxima

Find the local maximum of f(x)={ log(x) } / x .
I tried but could only find local minima .After first derivate making it equal to 0,i got only one solution i.e., x=e  and this solution gave local minima.Please help me in finding local maxima

Grade:12th pass

2 Answers

Aditya Gupta
2081 Points
3 years ago
y= logx/x
we see that domain is (0, inf)
dy/dx= f’(x)= (1 – logx)/x^2, which is positive for x less than e and negative for x greater than e. at x=e, it is 0.
hence by first derivative test, x= e is the local (as well as global in this case!) maxima.
kindly approve :)
Vikas TU
14149 Points
3 years ago
Dear student 
You are correct , X = e will be tha ans , 
You yourself told the explanton , 
Good Luck 
Cheers 

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