Khimraj
Last Activity: 7 Years ago
The meeting point of above two curve are (0,0) and (4,4)
So we have to find out normal to curve x3 + y3 = 8xy at point (4,4)
differentiating above equation
3x2 +3y2m = 8y +8xm where m = y’
putting x =4 and y=4
48 + 48m = 32 + 32m
16m = -16
m = -1
slope of normal at (4,4) = -1/m = 1
So equation of normal
(y-4) = 1(x-4)
So y = x.
Hope it clears.
