find the diiferential equation of first order and first degree dy/dx = sin (x+y)

Question

find the diiferential equation of first order and first degree dy/dx = sin (x+y)

Aditya Gupta · Answer

the ques seems a bit wrongly worded. so i will answer what i understood it as. the order of diff eqn is 1 and degree is also 1. now to solve we can put z=x+y so that dz/dx = 1+dy/dx= 1+ sin (x+y)= 1+sinz or dz/(1+sinz)= dx integrate both sides C – 2/(1+tan(z/2)) = x or 2/[1+tan((x+y)/2)] + x= C

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find the dii\fferential equation of first order and first degree dy/dx = sin (x+y)

find the dii\fferential equation of first order and first degree
dy/dx = sin (x+y)

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