Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Live 1-1 coding classes to unleash the creator in your Child
Find limit x tends to 0 for { x.log(1+2tanx) }/(1-cosx)
Dear student x² log ( 1 + 2 tanx) *2 tanx/x* 2 tanx(1 - cosx) Now put limit 1 * 2 * 2 = 4 Hope it helps Thanks
write it as[x/(1 – cosx)]*[log(1+2tanx)/2tanx]*2tanxso, lim becomes (limit x tends to 0 2xtanx/(1 – cosx))*(limit x tends to 0 log(1+2tanx)/2tanx)= (limit x tends to 0 2xtanx/(1 – cosx))*(limit y tends to 0 log(1+y)/y).....here we have let y= 2tanx= (limit x tends to 0 2xtanx/(1 – cosx))*1= limit x tends to 0 2xsinx/cosx(1 – cosx)= limit x tends to 0 2xsinx(1+cosx)/cosx(1 – cos^2x)= limit x tends to 0 2xsinx(1+cosx)/cosxsin^2x= limit x tends to 0 2x(1+cosx)/cosxsinx= limit x tends to 0 [2(1+cosx)/cosx] * limit x tends to 0 x/sinx= 4*1= 4kindly approve :)
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -