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find limit x tends to 0 for sin(180cos^2x) and what i sa its answer show me step by step that will be your most kindness

find limit x tends to 0 for sin(180cos^2x) and what i sa its answer show me step by step that will be your most kindness

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Grade:11

2 Answers

Vinod Prajapati
22 Points
3 years ago
Limit x tends t 0 sin(180cos^2x)=0Steps:Limit x tends t 0 sin(180cos^2x)=sin(180cos^2(0)) =Sin(180*1^2) = Sin(180) =0. . . . . .(sin180=0)
Ayush
36 Points
3 years ago
Apply l hospital rule for faster approach or open cos^2x as 1-sin^2x then your function will be reduced to sin3.14sin^2/x^2. now multiply and divide with pie use standard result and now your answer will come as pie

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