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Let y1=xx
Taking log on both sides, get
Logy1=xlogx
Diff w. r. to x ,get
1/y1. Dy1/dx=x.1/x+logx.1
Dy1/dx=y1[1+logx]
=xx[1+logx]
10^x = e^(x ln 10)
thus dy/dx=ex+10xln10 +xx(1+logx)
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Rinkoo Gupta
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