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question mark

find dy/dx when
y=x^x + x^1/x

taniska , 11 Years ago
Grade 12
anser 1 Answers
Revathi Mukkamala
Let u = x^x
log u = x log x
differentiating wrt x we get du/dx
Let v = x^1/x
log v = (1/x) log x
diff we get. dv/dx
y = u + v
dy/dx = du/dx + dv/dx
Last Activity: 11 Years ago
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