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Grade: 12 
        
find dy/dx when
y=x^x + x^1/x
5 years ago

Answers : (1)

Revathi Mukkamala
8 Points 
							
Let u = x^x
log u = x log x
differentiating wrt x we get du/dx
Let v = x^1/x
log v = (1/x) log x
diff we get. dv/dx
y = u + v
dy/dx = du/dx + dv/dx
5 years ago
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