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Grade: 12th pass
        
Find differential equations dy/dx, if  y = sec-1 (1+x2​/2x)
29 days ago

Answers : (1)

Arun
21974 Points
							
Dear student
 
it is not called find differential equation.
It is called as find derivatives.
 
Now secy = 1 + x^2 /2x
 
sec y = 1/2x + x/2
 
sec y tan y dy/dx = ln(x)/2 + ½
 
Hence dy/dx = (1 + ln x) /(2 ( sec y tan y))
29 days ago
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