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Grade: 12
        Find differential coefficient dy/dvx if y=epowerx /logx
2 years ago

Answers : (1)

jitender
114 Points
							y=e^x /logxdy/dx = d[(e^x)/logx]/dx= ~~~> d u/v / x = [vdu/dx - udv/dx]/v^2So dy/dx = [logx (e^x) - e^x (1/x)]/log^2x= e^x [ logx - 1/x]/logx..............And de^x/dx=e^xAnd dlogx/x=1/x
						
2 years ago
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