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find d2y/dx2 where y=log(x^2/e^2)
y=log(x2/e2)diff. w.r. to x , we getdy/dx=1/(x2/e2) . (2x/e2)=2/xdiff. w.r. to x againd2y/dx2 =-2/x2Thanks & RegardsRinkoo GuptaAskIITians Faculty
y=log(x2/e2) diff. w.r. to x , we get dy/dx=1/(x2/e2) . (2x/e2) =2/x diff. w.r. to x again d2y/dx2=-2/x2 Thanks & Regards Rinkoo Gupta AskIITians Faculty
y=log(x2/e2)
diff. w.r. to x , we get
dy/dx=1/(x2/e2) . (2x/e2)
=2/x
diff. w.r. to x again
d2y/dx2=-2/x2
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty
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