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F(x)=x+tanx,f(x) is inverse of g(x) differentiation of g(x) is equal to
Since g is inverse of f, thereforef(g(x))= xf'(g(x))*g'(x)=1But f'(x)= 1+sec^2xSo g'(x)= 1/(1+sec^2g(x))
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