f(x+a)= 1/2 + sqrt(f(x)-(f(x))^2) holds for all x. Prove that the function is periodic
Pranjal K , 11 Years ago
Grade upto college level
Differential Calculus> functions...
1 AnswersParvez ali
Last Activity: 11 Years ago
f(x+a)= 1/2 + sqrt(f(x)-(f(x))^2)
thus f(x+a)>1/2,
f(x+2a)= 1/2 + sqrt(f(x+a)-(f(x+a))^2)
now see the image for further calculations
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