f(1)=3 , f’(1)=2 , then d/dx{log f(ex + 2x)} at x =0 is - 2/3
- 3/2
- 2
- 0
f(1)=3 , f’(1)=2 , then d/dx{log f(ex + 2x)} at x =0 is
- 2/3
- 3/2
- 2
- 0
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