f(0)=f(1)=0,f / (1)=2 &y=(e x )e f(x) dy/dx=

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vivek · Answer

let, g’(0)=f’(1)e f(0) +f(1)e f(0) .f(0) =f’(1)+f’(0)=0+2=2

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f(0)=f(1)=0,f / (1)=2 &y=(e x )e f(x) dy/dx=

f(0)=f(1)=0,f^/ (1)=2 &y=(e^x )e^f(x)
dy/dx=

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f(0)=f(1)=0,f / (1)=2 &y=(e x )e f(x) dy/dx=

f(0)=f(1)=0,f / (1)=2 &y=(ex )ef(x)dy/dx=

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f(0)=f(1)=0,f^/ (1)=2 &y=(e^x )e^f(x)
dy/dx=