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Evaluate :- lim x → 0 (1-cosx root(cos2x))/(e^(x^2)-1)
Apply L-Hospital.it would become = > (0 + sinx root(cos2x) - cosx * 0.5*1/root(cos2x) * sin2x * 2)/e^(x^2) * 2xapply again .means again apply L-Hospital. if 0/0 indeterminat forms.
please apply brackets appropriately wherever necessaryplease apply brackets appropriately wherever necessary
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