Ujjwal Sharma
Last Activity: 7 Years ago
Start this question with basic definition of logarithm,go forward bracket by bracket.
log{log(x-1)}..... clearly x-1>0 ====> x>1..................(1)
now solve for second bracket.
log(x-1)>0
using inequality rule and as base of log is >1 so we can write
x-1>1 ====> x>2................(2)
both of these conditions should be carried out simultaneously so take their intersection
we get final answer x>2.....
ALL THE BEST.