Vikas TU
Last Activity: 8 Years ago
Yes,
Take f(x) = |x-1| + |x-2|
For case 1. when x
f(x) = -x+1 – x + 2 = -2x + 3
case 2. when x > = 2
f(x) = x-1+x-2
= 2x – 3
case 3
when 1
f(x) = x – 1 – x +2
= 1
Draw the graph for this given interval and U will come to know that it is continuos and non – differentaible at exactly two point.
Like this there can be number of modulus function U can think.
