# divide 15 into two parts such that the square of one multiplied with the cube of the other is minimum.

Arun Kumar IIT Delhi
8 years ago
Hi

$\\a+b=15 \\=>{da \over db} \\=>c=a^2b^3=-1 \\=>lnc=2lna+3lnb \\=>{2 \over a}{da \over db}+{3 \over b}=0 \\=>{3 \over b}={2 \over a} \\=>{b \over a}={3 \over 2} \\=>b={3a \over 2}$

Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty