Discuss thr continuity redegine so as to remove the discontinuity Solve limit x tends to 0 1-cos3x/xtanx

Question

Sandeep Bhamoo · Answer

Apply D.L. HOPITAL`S TULE two times that is differentiate numerator and denominator two times you would get - {9•cos(3x)}÷{2sec²x + 2x•secx•tanx} put x=0, answer is 9/2. Please do approve my answer if correct

Gitanjali Rout · Answer

apply l hospitals rule 2 times then you would get 9/2 on putting x is eQUAL TO 0 HAVE A NICE DAY ADWIT ASKIITIANS FORUM

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Discuss thr continuity redegine so as to remove the discontinuity Solve limit x tends to 0 1-cos3x/xtanx

Discuss thr continuity redegine so as to remove the discontinuity Solve limit x tends to 0 1-cos3x/xtanx

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Discuss thr continuity redegine so as to remove the discontinuity Solve limit x tends to 0 1-cos3x/xtanx

Discuss thr continuity redegine so as to remove the discontinuity Solve limit x tends to 0 1-cos3x/xtanx

2 Answers

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