differentiate xy=ae^x+be^-x+x^2 where a,b are arbitary constants
ajay , 8 Years ago
Grade 12th pass
Differential Calculus> differentiate xy=ae^x+be^-x+x^2 where a,b...
1 AnswersNandana
Last Activity: 8 Years ago
It’s simple derivative of y with respect to x
which is given by -
y=(ae^x+be^-x+x^2)/x
y = ae^x/x+be^-x/x+x
by using the formula that d(u/v) = v du -u dv/v^2 , we obtain
d/dx(y) = a [xe^x- e^x /x^2 ] +b [-x e^-x – e^-x/x^2]+1
simplify forther if you want !
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