differentiate xy=ae^x+be^-x+x^2 where a,b are arb

Question

differentiate xy=ae^x+be^-x+x^2 where a,b are arbitary constants

Nandana · Accepted Answer

It’s simple derivative of y with respect to x which is given by - y=(ae^x+be^-x+x^2)/x y = ae^x/x+be^-x/x+x by using the formula that d(u/v) = v du -u dv/v^2 , we obtain d/dx(y) = a [xe^x- e^x /x^2 ] +b [-x e^-x – e^-x/x^2]+1 simplify forther if you want !

Differential Calculus> differentiate xy=ae^x+be^-x+x^2 where a,b...

differentiate xy=ae^x+be^-x+x^2 where a,b are arbitary constants

ajay , 8 Years ago

Nandana

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differential calculus

Differential Calculus> differentiate xy=ae^x+be^-x+x^2 where a,b...

differentiate xy=ae^x+be^-x+x^2 where a,b are arbitary constants

ajay , 8 Years ago

Nandana

LIVE ONLINE CLASSES

Other Related Questions on differential calculus

the diameter of a roller is 84 cm and its length is 120 cm. it takes 500 complete revolution to move once over to level a playground. find the area of the playground in square m?

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Find dy/DX when y=x^sinx+sin-1√x.

Please give me the solution of this problem.

Example 20. (i) In a AABC, find the maxima and minima of u = sin A sin B sin C
where A + B + C = T
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