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differentiate the following function with respect to x e^sin x + (tan x)^x

differentiate the following function with respect to x
e^sin x + (tan x)^x

Grade:12

2 Answers

Rinkoo Gupta
askIITians Faculty 80 Points
7 years ago

let y1=esinx

apply chain rule

dy/dx=esinx.cosx

let y2=tanxx

taking log on both sides

logy2=xlogtanx

diff.w.r.to x , we get

(1/y2)dy2/dx=x.(1/tanx)sec2x +logtanx.1

dy2/dx=tanxx[x/(sinxcosx)+logtanx]

hence dy/dx=esinx.cosx+tanxx[x/(sinxcosx)+logtanx]

Thanks & Regards

Rinkoo Gupta

AskIITians Faculty

Arun Kumar IIT Delhi
askIITians Faculty 256 Points
7 years ago
Hello
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty

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