differentiate the following function with respect to x

x^(sin x – cos x) + (x)^2 – 1/ (x)^2 + 1

^logy₁^{=(sinx-cosx)logx}

^{(1/y1)dy1/dx=(sinx-cosx)(1/x)+(logx)(cosx+sinx)}

^dy1/dx=x^(sinx-cosx)[(sinx-cosx)/x+(logx)(cosx+sinx)]

hence,dy/dx=x^(sinx-cosx)[(sinx-cosx)/x+logx(sinx+cosx)]+2x-2(x)^-3

^{Thanks & Regards}

^{Rinkoo Gupta}

^{AskIITiansFaculty}