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Grade: 12
        
differentiate the following function with respect to x
(x^x) . (sqrt x)
5 years ago

Answers : (1)

Rinkoo Gupta
askIITians Faculty
80 Points
							

Let y1=xx

Taking log on both sides, get

logy1=xlogx

Diff w. r. to x ,get

(1/y1). dy1/dx=x.1/x+logx.1

dy1/dx=y1[1+logx]

=xx[1+logx]

Now using Product rule of diff. to the give function

dy/dx=xx(1/2√x)+√x. xx(1+logx)

Thanks & Regards

Rinkoo Gupta

AskIITians Faculty

5 years ago
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