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Let y1=xx
Taking log on both sides, get
logy1=xlogx
Diff w. r. to x ,get
(1/y1). dy1/dx=x.1/x+logx.1
dy1/dx=y1[1+logx]
=xx[1+logx]
Now using Product rule of diff. to the give function
dy/dx=xx(1/2√x)+√x. xx(1+logx)
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