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differentiate the following function with respect to xx^(sin^1(x))
y=xsinxtaking log on both sideslogy= Sinx logxusing product rule of diff.(1/y )dy/dx=sinx.(1/x)+logx.cosxdy/dx=xsinx[(sinx)/x+cosx logx]AskIITians FacultyRinkoo GuptaThanks & Regards
y=xsinx
taking log on both sides
logy= Sinx logx
using product rule of diff.
(1/y )dy/dx=sinx.(1/x)+logx.cosx
dy/dx=xsinx[(sinx)/x+cosx logx]
AskIITians Faculty
Rinkoo Gupta
Thanks & Regards
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