differentiate the following function with respect to x

x^(sin^1(x))

y=x^sinx

^{taking log on both sides}

logy= Sinx logx

using product rule of diff.

(1/y )dy/dx=sinx.(1/x)+logx.cosx

dy/dx=x^sinx[(sinx)/x+cosx logx]

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Rinkoo Gupta

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