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differentiate the following function with respect to x(sin^-1(x))^x
Y=(sin-1x)xtaking log on both sideslogy=xlogsin-1x(1/y )dy/dx=x.1/sin-1x.1/√(1-x2) +logsin-1x .1dy/dx=(sin-1x)x[x/{sin-1x√(1-x2)}+logsin-1x]AskIITians FacultyRinkoo GuptaThanks & Regards
Y=(sin-1x)x
taking log on both sides
logy=xlogsin-1x
(1/y )dy/dx=x.1/sin-1x.1/√(1-x2) +logsin-1x .1
dy/dx=(sin-1x)x[x/{sin-1x√(1-x2)}+logsin-1x]
AskIITians Faculty
Rinkoo Gupta
Thanks & Regards
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