differentiate the following function with respect to x10^(10^x)

y=(10)^{(10)^x}

taking log on both sides

logy=10^xlog10

diff. w.r. to x,we get

(1/y)dy/dx=(log10).10^xlog10

dy/dx==(10)^{(10)^x}[10^x . (log10)²]

Thanks & Regards

Rinkoo Gupta

AskIITians Faculty