differentiate the following function with respect to x

10^(log sin x)

y=10^logsinx

^{taking log on both sides}

logy=logsinx log10

diff.w.r. to x , we get

(1/y) dy/dx=(1/sinx)(cosx) .log10

dy/dx=10^logsinx[cotx log10]

Thanks & Regards

Rinkoo Gupta

askIITians Faculty