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differentiate the following function with respect to x (sin x)^ log x

differentiate the following function with respect to x
(sin x)^ log x

Grade:12

1 Answers

Rinkoo Gupta
askIITians Faculty 81 Points
9 years ago

y=(sinx)logx

logy=logx. Logsinx

(1/y)dy/dx=logx.(1/sinx)(cosx)+logsinx. (1/x)

dy/dx=sinxlogx[cotx.logx +(1/x)logsinx]

Thanks & Regards

Rinkoo Gupta

AskIITians Faculty

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