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y=xsinx
taking log on both sides
logy=sinx.logx
diff.w.r.to x using product rule of two function
(1/y)dy/dx=sinx.(1/x)+logx(cosx)
dy/dx=xsinx[(sinx)/x +cosx logx]
Thanks & Regards
Rinkoo Gupta
askIITians Faculty
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