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differentiate the following function with respect to x log(x^2+x+1/x^2-x+1)
y=log(x2+x+1)-log(x2-x+1)y=log{x-1)(x2+x+1)/(x-1)} -log{((x+1)(x2-x+1)/(x+1)}=log(x3-1)-log((x-1) -log(x3+1) +log(x+1)=log((x3-1)/(x3+1)) +log((x+1)/(x-1))Thanks & RegardsRinkoo GuptaAskIITians Faculty
HiPlease evaluate yourself.Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty
Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty
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