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differentiate the following function with respect to x e^(x) log x/x^2
y=(exlogx)/x2dy/dx=[x2{ex/x+logx.ex}-exlogx.2x]/x4=[xex+logx.ex(x2-2x)]/x4=[ex+logx.ex(x-2)]/x3Thanks & RegardsRinkoo GuptaAskIITians Faculty
HiThanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty
Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty
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