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differentiate the following function with respect to xe^(x) sin x/(x^2 +2)^3
y=(exsinx)/(x2+2)3diff. w. r. to xdy/dx=[(x2+2)3{excosx+sinx.ex}-(exsinx)3(x2+2)2.2x]/(x2+2)6=[ex(x2+2)(sinx+cosx)-6xexsinx]/(x2+2)4 Thanks & RegardsRinkoo GuptaAskIITians Faculty
y=(exsinx)/(x2+2)3diff. w. r. to xdy/dx=[(x2+2)3{excosx+sinx.ex}-(exsinx)3(x2+2)2.2x]/(x2+2)6=[ex(x2+2)(sinx+cosx)-6xexsinx]/(x2+2)4
Thanks & RegardsRinkoo GuptaAskIITians Faculty
HiApplying chain rule.Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty
Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty
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