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Grade: 12th pass
        
Differential equation is ylogy dx + (x-log y) dy = 0. Can anyone tell me the approach to find general solution?
 
one year ago

Answers : (1)

Sai Bhargavi
18 Points
							
By rearranging the give differential equation we get , dx/dy =1/y -x/(ylogy)
   dx/dy + x/(ylogy) =1/y
    Now, calculate the integrating factor (IF),
    e∫1/(ylogy)=I.F
    Taking, logy=t (say)
     differentiating on both sides we get, dy=ydt
      IF=e∫dt/t=elogt=t, where t=logy
     now, solving in linear differential equation form
    x(t)= ∫t/y dy, since dy=ydt
   xt = ∫t
 xt=t2/2 +c
ie x(logy)=(logy)2/2 =c
one year ago
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