d/dx [(x+1)(x 2 +1)(x 4 +1)(x 8 +1)] =( 15x p - 16x q + 1)(x-1) -2 Then (p,q) =?

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Deepak Kumar Shringi · Answer

First simplify by multiplying and dividing by (x-1) apply formula of a 2 -b 2 = (a+b)(a-b)

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d/dx [(x+1)(x 2 +1)(x 4 +1)(x 8 +1)] =( 15x p - 16x q + 1)(x-1) -2 Then (p,q) =?

d/dx [(x+1)(x²+1)(x⁴+1)(x⁸+1)] =( 15x^p- 16x^q + 1)(x-1)^-2
Then (p,q) =?

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d/dx [(x+1)(x 2 +1)(x 4 +1)(x 8 +1)] =( 15x p - 16x q + 1)(x-1) -2 Then (p,q) =?

d/dx [(x+1)(x2+1)(x4+1)(x8+1)] =( 15xp - 16xq + 1)(x-1)-2 Then (p,q) =?

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d/dx [(x+1)(x²+1)(x⁴+1)(x⁸+1)] =( 15x^p- 16x^q + 1)(x-1)^-2
Then (p,q) =?