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Grade: 11
        
d/dx of sinx sin2x sin3x give me the answer please  derivation with step  by step
2 months ago

Answers : (3)

Saurabh Koranglekar
askIITians Faculty
6852 Points
2 months ago
Aditya Gupta
2014 Points
							
y= sinxsin2xsin3x
lny= lnsinx + lnsin2x + lnsin3x 
Differentiate both sides wrt x using chain rule
y'/y= cosx/sinx + 2cos2x/sin2x + 3cos3x/sin3x
Hence,
y'= cosxsin2xsin3x + 2cos2xsinxsin3x + 3cos3xsinxsin2x.
KINDLY APPROVE :))
2 months ago
Arun
24494 Points
							
Dear student
 
For differentiation, we should use chain rule
 
dy/dx = cos x sin2x sin3x + 2 sinx cos2x sin3x + 3 sinx sin2x cos3x
 
Hope it is helpful
2 months ago
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