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Cot^- {(√1+sinx) + (√1-sinx)÷(√1+sinx)-(√1-sinx)} solve this for me in easy steps Cot^- {(√1+sinx) + (√1-sinx)÷(√1+sinx)-(√1-sinx)} solve this for me in easy steps
Rationalise with respect to the denominatorThen u ll get 2 (1+cosx)/2sinx(1+cosx)/sinx= 2cos^2x / (2sinx/2cosx/2)Cot^- (cosx/2 / sinx/2)Cot^- (cotx/2)x/2
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