Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Can u solve it? Question number 13 plz

Can u solve it? Question number 13 plz

Question Image
Grade:11

1 Answers

Riddhish Bhalodia
askIITians Faculty 434 Points
5 years ago
By expanding the tan2x and cos2x terms we get

L = lim_{x\rightarrow 0} \frac{x(\frac{2tan(x)}{1-tan^2(x)} -2tan(x))}{4sin^4(x)}
simplifying we get

L = 0.5 lim_{x\rightarrow 0}\frac{x}{sin(x)}\frac{1}{cos^3(x)}\frac{1}{1-tan^2(x)}
now each of the multiplying term has limit 1 as x tends to 0 thus
L = 1/2

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free