 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
Can anyone please explain this one? The answer is A, but I need the explanation

```
5 months ago

```							statement 2 is clearly true as it is a std property/theorem of limits.in statement 1, if we let h(x)= [x] and g(x)= sinx/x, then [sinx/x]= h(g(x)).hence lim x tends to 0 [sinx/x] and [lim x tends to 0 (sinx/x)] would have been equal if h(x) were continuous at x= lim x tends to 0 g(x)= x= lim x tends to 0 sinx/x= 1. but obviously h(x)= [x] is discontinuous at x= 1.in fact using sinx/x= sin|x|/|x| and sin|x| is less than |x| for x not equal to 0 (this can be observed from graph), we can say that lim x tends to 0 [sinx/x]= 0 and [lim x tends to 0 (sinx/x)]= = 1. so they arent equal.hence option A.KINDLY APPROVE ;))
```
5 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Differential Calculus

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 51 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions