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As x approaches to infinite sin (x) approaches to --------------

As x approaches to infinite sin (x) approaches to --------------

Grade:NULL

1 Answers

Riddhish Bhalodia
askIITians Faculty 434 Points
5 years ago
the limit does not exist!
suppose a number at infinity isx = \pi(4n+1)/2 \quad or \quad x = \pi(4n+3)/2
as n tend to infinity will reuslt in different values of limit, hence it does not exist

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