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As x approaches to infinite sin (x) approaches to --------------

srinivas aytha , 9 Years ago
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Riddhish Bhalodia
the limit does not exist!
suppose a number at infinity isx = \pi(4n+1)/2 \quad or \quad x = \pi(4n+3)/2
as n tend to infinity will reuslt in different values of limit, hence it does not exist
Last Activity: 9 Years ago
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