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Grade 12IIT JEE Entrance Exam

Answer this question in limits (JEE mains level ).I got answer second option as answer , but how it is first option??

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Profile image of Karthik999
8 Years agoGrade 12
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1 Answer

Profile image of Amit
8 Years ago
Simplify it all in cos form..We get {(cos2x-cos4x)/(cosx-cos3x)}×{(cosx.cos3x)/(cos2x.cos4x)}.Use CosC-CosD formula..We get (Sin3x.cosx.cos3x)/(sin2x.cos4x.cos2x).Use Sinx/x=1 and solve to get answer 3/2.Hope it Helps..

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