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Answer this question in JEE mains level limits Class 12

Karthik999 , 8 Years ago
Grade 12
anser 1 Answers
Amit
Use the expansion of a^x= 1+ x/1!(loga)+x²/2!(loga)²+.... Now since x is approaching 0 neglect all terms other then first two... Now it will be {1+(x×logn!)/n}^(1/x).. Now use (1+x)^1/x= e ...On solving we get Answer as (B).
Last Activity: 8 Years ago
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