A student perform experiment with simple pendulum and measure time for 10 vibrations . If he measure a time for 100 vibrations , the relative error in measurement of timeperiod will be reduced by what % ? pls explain in detail .

Question

Arun · Answer

If the relative error in meauring time period out of 10 measurements is ΔT
Then, the relative error in measuring time period out of 100 measurements is ΔT/10
Thus, reduction in relative error = (ΔT - ΔT/10)/100
Therefore, % reduction = 90%

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A student perform experiment with simple pendulum and measure time for 10 vibrations . If he measure a time for 100 vibrations , the relative error in measurement of timeperiod will be reduced by what % ? pls explain in detail .

A student perform experiment with simple pendulum and measure time for 10 vibrations . If he measure a time for 100 vibrations , the relative error in measurement of timeperiod will be reduced by what % ? pls explain in detail .

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A student perform experiment with simple pendulum and measure time for 10 vibrations . If he measure a time for 100 vibrations , the relative error in measurement of timeperiod will be reduced by what % ? pls explain in detail .

A student perform experiment with simple pendulum and measure time for 10 vibrations . If he measure a time for 100 vibrations , the relative error in measurement of timeperiod will be reduced by what % ? pls explain in detail .

1 Answers

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Other Related Questions on Differential Calculus

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