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A point is moving along the curve y 3 =27x.Find the interval of values of x in which ordinate changes faster than the abscissa
Dear student y^3 = 27x 3y^2 dy = 27 dx dy/dx = 9/y^2 we want the interval such that dy > dx dy/dx > 1 9/y^2 > 1 y^2 – 9 y belongs to ( – 3, 3) – {0} when y = – 3 -27 = 27 x x = – 1 similarily when y = 1, x = 1 x belongs to ( – 1, 1) – {0} RegardsArun
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