a circle with centre at (-15,3) is a tangent to y

Question

a circle with centre at (-15,3) is a tangent to y=x^2/3 at a point in the first quadrant the radius of the circle is equal to AOD

Abhi singhal · Accepted Answer

centre is given (-15.3) and tangent is y=x^2/3 the in first quadrant the radius of circle AOD is 15/8^1/2 as it is the short cut trick given in the book rd sharma see it

Differential Calculus> a circle with centre at (-15,3) is a tang...

a circle with centre at (-15,3) is a tangent to y=x^2/3 at a point in the first quadrant the radius of the circle is equal to AOD

suyash , 7 Years ago

Abhi singhal

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differential calculus

Differential Calculus> a circle with centre at (-15,3) is a tang...

a circle with centre at (-15,3) is a tangent to y=x^2/3 at a point in the first quadrant the radius of the circle is equal to AOD

suyash , 7 Years ago

Abhi singhal

Provide a better Answer & Earn Cool Goodies

LIVE ONLINE CLASSES

Ask a Doubt

Other Related Questions on differential calculus

the diameter of a roller is 84 cm and its length is 120 cm. it takes 500 complete revolution to move once over to level a playground. find the area of the playground in square m?

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differential calculus

Find dy/DX when y=x^sinx+sin-1√x.

Please give me the solution of this problem.

Example 20. (i) In a AABC, find the maxima and minima of u = sin A sin B sin C
where A + B + C = T
(ii) In a plane triangle ABC, find the maximum value of cosA cosB cosC.