0

Guest

Courses New

a circle with centre at (-15,3) is a tangent to y=x^2/3 at a point in the first quadrant the radius of the circle is equal to AOD

a circle with centre at (-15,3) is a tangent to y=x^2/3 at a point in the first quadrant the radius of the circle is equal to AOD

Grade:11

1 Answers

Abhi singhal
39 Points
5 years ago
centre is given (-15.3) and tangent is y=x^2/3 the in first quadrant the radius  of circle AOD is 15/8^1/2 as it is the short cut trick given in the book rd sharma see it

Think You Can Provide A Better Answer ?

Other Related Questions on Differential Calculus

View all Questions »

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More