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2x-5 /(x-1)(x-2)(x-5) find out the partial fraction of above function
Dear student 2x-5/(x-1)(x-2)(x-5) = A/(x-1) + B/(x-2) + C/(x-5) A = – ¾B = 1/3C = 5/12 hence 2x-5/(x-1)(x-2)(x-5) = – 3/4(x-1) + 1/3(x-2) + 5/12(x-5)
Dear student Please follow this link https://www.askiitians.com/iit-jee-indefinite-integral/algebraic-integrals/Good Luck
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