2x-5 /(x-1)(x-2)(x-5) find out the partial fraction of above function

Question

Arun · Answer

Dear student 2x-5 /(x-1)(x-2)(x-5) = A/(x-1) + B/(x-2) + C/(x-5) A = – ¾ B = 1/3 C = 5/12 hence 2x-5 /(x-1)(x-2)(x-5) = – 3/4(x-1) + 1/3(x-2) + 5/12(x-5)

Vikas TU · Answer

Dear student Please follow this link https://www.askiitians.com/iit-jee-indefinite-integral/algebraic-integrals/ Good Luck

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2x-5 /(x-1)(x-2)(x-5) find out the partial fraction of above function

2x-5/(x-1)(x-2)(x-5) find out the partial fraction of above function

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