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f(x) = [sin(cosx) - cosx] / (Π-2x) 2 , x is not Π/2 k ,x=Π/2 is continuos at x= Π/2 then k is equal to ?

f(x) = [sin(cosx) - cosx] / (Π-2x)2    , x is not Π/2


         k  ,x=Π/2


is continuos at x= Π/2 then k is equal to ?


 

Grade:12

1 Answers

saiomkar kandukuri
33 Points
9 years ago

f(x) is continuous at x=pi/2   so left hand limit is equal to right hand limit is equal to value of function at given pt

   so the left hand limiting value is found by applying L-Hopital''s rule three times.....the limit value is equal to k

it is functional value

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