Check continuityf(x) = e^1/x - 1/(e^1/x +1) , x is nt equal to 00 , x=0

Dear Shefali Sharma,

Ans:- f(x)=e^1/x - 1/(e^1/x+1)

Lt x tends to 0 from + i.e x=0+h=∞

Lt x tends to 0 from negative i.e x=0-h= -1

Hence it is dicotinuous at x=0 

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